WEB TUTORIAL - Group Theory

H2O Worked Example
Applying the Reduction Formula

C2vEC2 (z)sigmav(xz)sigmav(yz)Linear functions,
rotations
Quadratic
functions
Cubic
functions
A1+1+1+1+1zx2, y2, z2z3, x2z, y2z
A2+1+1-1-1Rzxyxyz
B1+1-1+1-1x, Ryxzxz2, x3, xy2
B2+1-1-1+1y, Rxyzyz2, y3, x2y
Number of symmetry elements, h = 4

Now we have all of the required parts, we simply put them together into the Reduction Formula one row at a time.

It is worth doing this on a piece of paper rather than in your head before checking your answers!

reduction formula

Key: The numbers in each representation are: N x R x I

To calculate the number of A1 representations we focus on the values of I for this representation, which are +1 for each operation.
For E: 1 x 2 x 1 = 2
For C2: 1 x 0 x 1 = 0
For sigmav(xz): 1 x 2 x 1 = 2
For sigmav'(yz): 1 x 0 x 1 = 0
The summation of these terms is 4 (2+0+2+0). The number of symmetry elements (h Term) is 4, and hence the number of A1 representations is: 1/h x (4) = 1.

To calculate the number of A2 representations we focus on the values of I for this representation, which are +1, +1, -1, -1.
For E: 1 x 2 x 1 = 2
For C2: 1 x 0 x 1 = 0
For sigmav(xz): 1 x 2 x -1 = -2
For sigmav'(yz): 1 x 0 x -1 = 0
The summation of these terms is 0.

To calculate the number of B1 representations we focus on the values of I for this representation, which are +1, -1, +1, -1.
For E: 1 x 2 x 1 = 2
For C2: 1 x 0 x -1 = 0
For sigmav(xz): 1 x 2 x 1 = 2
For sigmav'(yz): 1 x 0 x -1 = 0
The summation of these terms is 4 (2+0+2+0). The number of symmetry elements (h Term) is 4, and hence the number of B1 representations is: 1/h x (4) = 1.

To calculate the number of B2 representations we focus on the values of I for this representation, which are +1, -1, -1, +1.
For E: 1 x 2 x 1 = 2
For C2: 1 x 0 x -1 = 0
For sigmav(xz): 1 x 2 x -1 = -2
For sigmav'(yz): 1 x 0 x 1 = 0
The summation of these terms is 0.

So there is one A1 and one B1 representation.
So what does this mean? ⇒