WEB TUTORIAL - Group Theory
H2O Worked ExampleApplying the Reduction FormulaNumber of symmetry elements, h = 4
C2v E C2 (z) v(xz) v(yz) Linear functions,
rotationsQuadratic
functionsCubic
functionsA1 +1 +1 +1 +1 z x2, y2, z2 z3, x2z, y2z A2 +1 +1 -1 -1 Rz xy xyz B1 +1 -1 +1 -1 x, Ry xz xz2, x3, xy2 B2 +1 -1 -1 +1 y, Rx yz yz2, y3, x2y Now we have all of the required parts, we simply put them together into the Reduction Formula one row at a time.
It is worth doing this on a piece of paper rather than in your head before checking your answers!
Key: The numbers in each representation are: N x R x I
To calculate the number of A1 representations we focus on the values of I for this representation, which are +1 for each operation.
For E: 1 x 2 x 1 = 2
For C2: 1 x 0 x 1 = 0
For v(xz): 1 x 2 x 1 = 2
For v'(yz): 1 x 0 x 1 = 0
The summation of these terms is 4 (2+0+2+0). The number of symmetry elements (h Term) is 4, and hence the number of A1 representations is: 1/h x (4) = 1.To calculate the number of A2 representations we focus on the values of I for this representation, which are +1, +1, -1, -1.
For E: 1 x 2 x 1 = 2
For C2: 1 x 0 x 1 = 0
For v(xz): 1 x 2 x -1 = -2
For v'(yz): 1 x 0 x -1 = 0
The summation of these terms is 0.To calculate the number of B1 representations we focus on the values of I for this representation, which are +1, -1, +1, -1.
For E: 1 x 2 x 1 = 2
For C2: 1 x 0 x -1 = 0
For v(xz): 1 x 2 x 1 = 2
For v'(yz): 1 x 0 x -1 = 0
The summation of these terms is 4 (2+0+2+0). The number of symmetry elements (h Term) is 4, and hence the number of B1 representations is: 1/h x (4) = 1.To calculate the number of B2 representations we focus on the values of I for this representation, which are +1, -1, -1, +1.
For E: 1 x 2 x 1 = 2
For C2: 1 x 0 x -1 = 0
For v(xz): 1 x 2 x -1 = -2
For v'(yz): 1 x 0 x 1 = 0
The summation of these terms is 0.So there is one A1 and one B1 representation.
So what does this mean? ⇒